Balancing Centrifuges with Number Theory
Balancing Centrifuges with Number Theory
复制标题
用数论平衡离心机
DOI:
10.1080/10724117.2022.2092372
复制
发表时间:
2022
期刊:
影响因子:
--
通讯作者:
Baker, Matthew H.
中科院分区:
文献类型:
--
作者:
Baker, Matthew H.
Title and figure 2 photos courtesy of Rishav Ray (Reddit; https://bit. ly/3zI5vvN) www. maa. org/mathhorizons Math Horizons| September 2022 21 www. maa. org/mathhorizons Math Horizons| September 2022 21 should be able to convince yourself that k= 1 and k= 5 test tubes won’t balance when n= 6. When n= 5 or n= 7, it turns out you can only balance the centrifuge when k= n. From these first few cases, we should guess that the answer might have something to do with whether n is prime… let’s look at a few more examples. When n= 8, you can balance the centrifuge if and only if k is even, and when n= 9, you can balance the centrifuge when k is a multiple of 3. When n= 11, you can only balance if k= 11.But something interesting happens when n= 10. In this case, you can find balanced centrifuges for k= 2, 4, 5, 6, 8, or 10. Notice, for example, that if you wanted to balance the centrifuge with k= 7, you could try to start with a balanced set of five test tubes (occupying every other slot as in figure 4) and then add two more in opposite holes, but there’sa problem: one out of each pair of opposite holes is already occupied! We will call this the overlap problem. In some sense, the overlap problem is the key subtlety in the balanced centrifuge problem. Let’s look at one more example. When n= 21, you can balance if and only if k is in the set {3, 6, 7, 9, 12, 14, 15, 18, 21}. We can see yet another illustration of the overlap problem by considering the case k= 10. You could try to take a balanced configuration of seven test tubes (evenly spaced every three spots as in figure 4) and then add three more in the shape of an equilateral triangle, but you will find that it doesn’t work.