Stability of non-Fermi liquid in Kondo effect due to (5f)2configuration
Stability of non-Fermi liquid in Kondo effect due to (5f)2configuration
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由于 (5f)2 配置，近藤效应中非费米液体的稳定性
DOI：
10.1143/jpsj.66.1485
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发表时间：
1997
影响因子：
1.7
通讯作者：
H. Shiba
中科院分区：
文献类型：
--
作者：
M. Koga;H. Shiba
通过考虑5个f电子的激发态，研究了近藤效应中非费米液体的稳定性。首先，为了考察它们在强关联极限下的影响，通过将f2中的局域态限制为非Kramers双态和单态，导出了四方晶场的交换模型，并考虑了f1中的所有态。对该模型的数值重整化群分析表明，f2中的单重态和f1中的一个激发态对NFL上的费米液体(FL)的稳定起着重要的作用。其次，通过考虑所有的局域激发态，对六重轨道简并的Anderson模型研究了同样的问题。FL和NFL之间的竞争敏感地取决于库仑耦合和Hund耦合、轨道各向异性和杂化项。六重轨道简并对实现NFL也很重要；事实上，对四重轨道简并Anderson模型的类似分析...
The stability of the non-Fermi liquid (NFL) in Kondo effect is studied by considering the excited states of the 5 f -electrons. First, in order to examine their effects in the strong correlation limit, the exchange model is derived for a tetragonal crystal field by restricting the localized states in f 2 to a non-Kramers doublet and a singlet; all the states are taken into account for f 1 . The numerical renormalization group analysis for this model shows that the singlet state in f 2 and one of the excited states in f 1 play an important role to stabilize the Fermi liquid (FL) over the NFL. Second, the same problem is examined for the six-fold orbitally degenerate Anderson model by considering all the local excited states. The competition between FL and NFL sensitively depends on the Coulomb and Hund couplings, the orbital anisotropy and the hybridization term. The six-fold orbital degeneracy is also important to realize NFL; in fact a similar analysis on the four-fold orbitally degenerate Anderson model...