THE METHOD OF CHABAUTY AND COLEMAN WILLIAM MCCALLUM AND
THE METHOD OF CHABAUTY AND COLEMAN WILLIAM MCCALLUM AND
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Chabauty 和 Coleman William McCallum 的方法
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发表时间:
2017
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通讯作者:
B. Poonen
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作者:
B. Poonen
This is an introduction to the method of Chabauty and Coleman, a p-adic method that attempts to determine the set of rational points on a given curve of genus g ≥ 2. We present the method, give a few examples of its implementation in practice, and discuss its effectiveness. An appendix treats the case in which the curve has bad reduction. 1. Rational points on curves of genus ≥ 2 We will work over the field Q of rational numbers, although everything we say admits an appropriate generalization to a number field. Let Q be an algebraic closure of Q. For each finite prime p, let Qp be the field of p-adic numbers (see [Kob84] for the definition). Curves will be assumed to be smooth, projective, and geometrically integral. Let X be a curve over Q of genus g ≥ 2. We suppose that X is presented as the zero set in some P of an explicit finite set of homogeneous polynomials. We may give instead an equation for a singular (but still geometrically integral) curve in A; in this case, it is understood that X is the smooth projective curve birational to this singular curve. Rational points on X can be specified by giving their coordinates. (A little more data may be required if a singular model for X is used.) Let X(Q) be the set of rational points on X. In 1922 L. Mordell [Mor22] conjectured that X(Q) is finite, and in 1983 this was proved by G. Faltings [Fal83]. Thus we have the following well-defined problem: Given X of genus ≥ 2 presented as above, compute X(Q). An argument of A. N. Parshin (see [Szp85]) shows that Faltings’ proof can be adapted to give an upper bound on the cardinality of X(Q). But Faltings’ proof is still ineffective in the sense that it does not provide an algorithm for finding the points in X(Q), even in principle. In fact, it is not known whether any algorithm is guaranteed to solve this problem. Even the case g = 2 seems hard. Nevertheless there are a few techniques that can be applied: see [Poo02] for a survey. On individual curves these seem to solve the problem often, perhaps even always when used Date: June 14, 2010. 2000 Mathematics Subject Classification. Primary 11G30; Secondary 14G05, 14K20.