Gamow-Teller transitions from 11 Li and 12 Be
Gamow-Teller transitions from 11 Li and 12 Be
复制标题
11 Li 和 12 Be 的伽莫夫泰勒跃迁
DOI：
10.1103/physrevc.56.847
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发表时间：
1997
影响因子：
3.1
通讯作者：
T. Otsuka
中科院分区：
文献类型：
--
作者：
Toshio Suzuki;T. Otsuka
研究了从{11}和{12}到{Be}的Gamow-Teller(GT)相变的强度分布。我们研究了跃迁的GT强度在哪里${}^{11}\mathm{Li}$${(3/2}_{\mathrm{gs}}^{\mathrm{\ensuremath{-}}}{)\ensuremath{\rightarrow}}^{11}{\mathrm{Be}}^{*}$(${1/2}^{\ensureath{-}}，$${3/2}^{\ensureath{-}}，$${5/2}^{\EnsureMath{-}}$)位于包含猝灭效应的位置，这是由于\EnsureMath{\Delta}空穴贡献。讨论了GT求和规则与晕结构效应之间的关系。发现$p$壳层和$mathm{sd}$壳层之间的间隙变窄，改变了GT强度分布的结构。我们进一步研究了GT从$^{12}到$\mathm{Be}的跃迁。$p$和$\mathm{sd}$壳层之间距离的缩小使跃迁强度变化到$^{12}\mathm{Be}$${(1}_{\mathm{gs}}^{+})$。跃迁强度${}^{12}{\mathrm{Be}\ensuremath{\rightarrow}}^{12}\mathrm{B}$的猝灭表明中子闭壳层结构发生了巨大的破坏。
The strength distributions of Gamow-Teller (GT) transitions from ${}^{11}\mathrm{Li}$ and ${}^{12}\mathrm{Be}$ are investigated. We study where the GT strengths of the transitions ${}^{11}\mathrm{Li}$ ${(3/2}_{\mathrm{gs}}^{\mathrm{\ensuremath{-}}}{)\ensuremath{\rightarrow}}^{11}{\mathrm{Be}}^{*}$ (${1/2}^{\ensuremath{-}},$ ${3/2}^{\ensuremath{-}},$ ${5/2}^{\ensuremath{-}}$) are located incorporating quenching effects due to the \ensuremath{\Delta}-hole contributions. The connection between the GT sum rule and effects of the halo structure of ${}^{11}\mathrm{Li}$ are discussed. The narrowing of the gap between the $p$ shell and the $\mathrm{sd}$ shell is found to change the structure of the GT strength distribution. The accuracy of the present calculation is tested for the GT decay from ${}^{9}\mathrm{Li}.$ We further study the GT transition from ${}^{12}\mathrm{Be}.$ The narrowing of the gap between the $p$ and $\mathrm{sd}$ shells varies the transition strength to ${}^{12}\mathrm{Be}$ ${(1}_{\mathrm{gs}}^{+})$ as well as the GT distribution. The quenching of the transition strength ${}^{12}{\mathrm{Be}\ensuremath{\rightarrow}}^{12}\mathrm{B}$ ${(1}_{\mathrm{gs}}^{+})$ suggests an enormous breaking of the neutron closed-shell structure of ${}^{12}\mathrm{Be}.$