Ferrate(VI) Oxidation of Hydrogen Sulfide

Ferrate(VI) Oxidation of Hydrogen Sulfide
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DOI:
10.1021/es960755z
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发表时间:
1997-08
影响因子:
11.4
通讯作者:
V. Sharma;Jeremy O. Smith;F. Millero
V. Sharma;Jeremy O. Smith;F. Millero
中科院分区:
环境科学与生态学1区
文献类型:
--
作者:
V. Sharma;Jeremy O. Smith;F. Millero

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硫化氢与Fe(VI)的氧化速率是在厌氧条件下作为pH值(7 - 12)和温度(5 - 15 °C)的函数进行的。发现反应对于每种反应物都是一级反应。在pH = 12时,活化能为30.1 ± 4.9 kJ mol ~(-1)。当[H2S]T([H2S] + [HS-])浓度过量时,在pH = 7.0时消耗的[H2S]T与消耗的[Fe(VI)]之比为1.51 ± 0.14,在pH = 9.0和11.3时为2.50 ± 0.13。硫代硫酸盐是pH = 7.0时的主要产物;亚硫酸盐、硫代硫酸盐和硫酸盐被鉴定为pH = 9.0和11.3时的反应产物。当[Fe(VI)]超过[H2S]T时,硫化氢被完全氧化成硫酸盐。提出了Fe(VI)单电子氧化H2S的机理。实验研究了铁离子对地下水和废水中硫化物的去除效果。实验结果表明,Fe(VI)可以作为一种有效的氧化剂用于脱除水中的硫化氢。
The rates of oxidation of hydrogen sulfide with Fe(VI) were made anaerobically as a function of pH (7−12) and temperature (5−15 °C). The reaction was found to be first order for each reactant. The rates decrease with an increase in pH. The energy of activation was found to be 30.1 ± 4.9 kJ mol-1 at pH = 12. When the concentrations of [H2S]T ([H2S] + [HS-]) are in excess, the ratio of [H2S]T consumed to [Fe(VI)] consumed was 1.51 ± 0.14 at pH = 7.0 and 2.50 ± 0.13 at pH = 9.0 and 11.3. Thiosulfate was the main product at pH = 7.0; sulfite, thiosulfate, and sulfate were identified as the products of the reactions at pH = 9.0 and 11.3. In an excess of [Fe(VI)] over [H2S]T, the hydrogen sulfide is fully oxidized to sulfate. A mechanism in which Fe(VI) oxidizes H2S by a one-electron process is proposed. Experiments were conducted to test the Fe(VI) removal efficiency of sulfide in groundwater and wastewater. The results indicate that Fe(VI) can be used as an effective oxidant to remove hydrogen sulfide from wa...