Deforming a hypersurface by its Gauss-Kronecker curvature
Deforming a hypersurface by its Gauss-Kronecker curvature
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DOI:
10.1002/cpa.3160380615
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发表时间:
1985-11
影响因子:
3
通讯作者:
K. Tso
中科院分区:
文献类型:
--
作者:
K. Tso
Recently there has been some interest in studying a curve-shortening problem: Consider a simple closed curve in the plane and deform it along the inner normal at a rate equal to its curvature. We wish to establish the existence of this deformation and its limiting behavior. M. Gage [6],[7] has shown that when the curve is strictly convex the deformation decreases the isoperimetric ratio and, furthermore, if it shrinks to a point p, the normalized curves, obtained by “blowing up” the curves centered at p so that its enclosed area is T, must tend to the unit circle in a certain sense. R. Hamilton [9] proved that the deformation exists, that is, the curves stay smooth and convex and shrink to a point at time A/27r, where A is the enclosed area of the initial curve. This problem can be generalized to higher dimensions as follows: Given a closed hypersurface X (s), s E S”, we study the solution of the initial value problem: ax-(s, t)=-k (s, t) N (s, t), at where k is the Gauss-Kronecker curvature and N is the outer unit normal at X (s, t). The variable s E S “should remain as a parametrization of the closed hypersurfaces X (s, t) for all t. In this paper we shall proveTHEOREM 0.1. Let X (s), s E S “, be a smooth, closed, strictly-convex hypersurface in W*+ I. Then (0.1) has a unique, smooth solution X (s, t) which is a strictly convex hypersurface for each t in [0, T*) where T*= V/an, V is the volume enclosed by X (s), and an is the surface area of S”. Furthermore, X (., t’) is strictly enclosed by X (., t) for t ‘> t. As t tends to T*, the hypersurfaces shrink to apoint.