Structural characterization of an enantiopure hydroxo-bridged binuclear iron(III) complex with empty one-dimensional helical channels
Structural characterization of an enantiopure hydroxo-bridged binuclear iron(III) complex with empty one-dimensional helical channels
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DOI:
10.1021/ic049145n
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发表时间:
2005-03-07
影响因子:
4.6
通讯作者:
Ray, M
中科院分区:
文献类型:
--
作者:
Alam, MA;Nethaji, M;Ray, M
A H-bond capable chiral tetradentate ligand, Fe3+, and acetate ion assembles into a hydroxo-bridged binuclear complex with the formula [Fe-2(III)(mu-OH)(mu-OAc)(S-L)(2)].4H(2)O (1) where H2S-L = S-2-(2-hydroxy-benzylamino)-3(1H-imidazol-4-yl)-propionic acid. The crystal of 1 contains right-handed one-dimensional (M) helical channels with 7.3-9.8 Angstrom diameter. A similar reaction with a ligand having opposite chirality forms the complex with left-handed helical channels (1a). Heating the crystals of 1 at 95 degreesC under reduced pressure selectively removes three waters from the channel forming an enantiopure porous crystal with empty channels (solvent accessible voids 18% v/v). Intermolecular hydrogen bonding between the imidazole N-H and phenolate oxygen in 1-2 forms a C-6 symmetric helix with bridging hydroxo, groups pointing inside the channels. All the H-bond capable atoms in the ligand along with one water molecule form an extended H-bonded network throughout the crystal. Exposing the empty channels of 2 to iodine vapor indicates partial filling of the channels with iodine. Crystal data for 1.4H(2)O include the following: hexagonal, P6(1), a = b = 13.164(3) Angstrom, c = 36.305 (11) Angstrom, alpha = beta = 90degrees, gamma = 120degrees, Z = 6, R1 = 0.0387, wR2 = 0.0842. Crystal data for 1.2H(2)O include the following: hexagonal, P6(5), a = b = 13.151(4) Angstrom, c = 36.558(2) Angstrom, alpha = beta = 90degrees, gamma = 120degrees, Z = 6, R1 = 0.0416, wR2 = 0.1190. Crystal data for 2.H2O include the following: hexagonal, P6(1), a = b = 13.160(7) Angstrom, c 36.559 (4) alpha, beta = 90degrees, 120degrees, Z = 6, R1 0.0574, wR2 = 0.1423.