Ternary system samarium-nitrogen-oxygen and the question of lower oxides of samarium
Ternary system samarium-nitrogen-oxygen and the question of lower oxides of samarium
复制标题
钐-氮-氧三元体系及钐低氧化物问题
DOI：
10.1021/ic50062a006
复制
发表时间：
1968
影响因子：
4.6
通讯作者：
L. Eyring
中科院分区：
文献类型：
--
作者：
T. Felmlee;L. Eyring
三元化合物SmNi-，0，（0< x< 0.5）已经制备; x= 0.5的制备物具有与以前认为是SmO的物质相同的性质。具有NaCl结构的SmNi_nOx的晶格常数随着x的增加而不断减小。这表明，当SmN中的氮被氧取代时，钐离子的3+价态被保留，尽管形式上，氧-氮交换必须导致等量的Sm 3+还原为Sm 2+。SmN^^ O暴露在大气中会发生水解，溶于酸中会放出氢。以前被认为是Sm 20的化合物实际上是SmH 2。
The ternary compounds SmNi-, 0,(0< x< 0.5) have been prepared; preparations where x= 0.5 have the same properties as substances previously thought to be SmO. The lattice parameter of SmNi_ „Ox, which has the NaCl structure, decreases continuously with increase in x. This suggests that as the nitrogen of SmN is replaced by oxygen, the 3+ valency of the samarium ion is retained although, formally, the oxygen-nitrogen exchange must result in the reduction of an equivalent amount of Sm3+ to Sm2+. SmN^^ O, undergoes hydrolysis on exposure to the atmosphere, and, on dissolving it in acid, hydrogen is evolved. The compound previously thought to be Sm20 was found to be, inreality, SmH2.