Edge-Disjoint Hamilton Cycles in Regular Graphs of Large Degree
Edge-Disjoint Hamilton Cycles in Regular Graphs of Large Degree
复制标题
大次数正则图中边不相交的哈密顿循环
DOI:
10.1112/jlms/s2-19.1.13
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发表时间:
1979
影响因子:
1.2
通讯作者:
B. Jackson
中科院分区:
文献类型:
--
作者:
B. Jackson
All graphs considered in this paper are simple. For x a real number, let [x] denote the largest integer which is less than or equal to x. We shall prove the following result. THEOREM 1. Let G be a k-regular graph on n vertices, where 14 ^ n < 2/r+l. Then G contains [iQk —n + l)] edge-disjoint Hamilton cycles. For h an integer, define a h to be zero if h is even and one if h is odd. Nash-Williams [5; Theorem 3] has proved the following. THEOREM 2. / / G is a graph on n vertices with minimum degree k, and n < 2k, then G contains [-jrzin + a n +10)] edge-disjoint Hamilton cycles. Theorem 1 implies that if G is a A:-regular graph on n vertices and n ^ 2k, then G contains Wr(n + 3a n + 2)] edge-disjoint Hamilton cycles. Thus we are able to increase the bound on the number of edge-disjoint Hamilton cycles by adding a regularity condition. In [5] Nash-Williams conjectured that if G satisfies the conditions of Theorem 2, then G contains [i(n + l)] edge-disjoint Hamilton cycles. Although counterexamples were subsequently constructed by L. Babai, Nash-Williams points out that his conjecture remains open for regular graphs [6; pp. 817-818]. We conjecture further, that if G is a A>regular graph on n vertices and n^2k+\ then G contains [%k] edge-disjoint Hamilton cycles. This conjecture is similar to one due to P. Kelly [4; p. 7] that any regular tournament can be decomposed into directed Hamilton cycles, since both conjectures imply that K 2m+l is, in some sense, "strongly decomposable" into Hamilton cycles. Our conjecture would imply that any set of [i(m-l-l)] edge-disjoint Hamilton cycles of K 2m+ i could be extended to a hamiltonian decomposition of K 2m+l. Kelly's conjecture would imply that if the edges of K 2m+1 are directed in such a way that the indegrees and outdegrees of every vertex are equal, then the resulting digraph has a hamiltonian decomposition. For any graph G, let V{G) denote the set of vertices, and E(G) the set of edges, of G. For H a subgraph of G and M and N subsets of V(H) let E H {M, N) denote the set, and e w (M, N) the number of edges between the vertices of M and the vertices of N. Further, let H [M] be the subgraph …