GLUCOSE HAS TO BE PHOSPHORYLATED TO ACTIVATE GLYCOGEN-SYNTHASE, BUT NOT TO INACTIVATE GLYCOGEN-PHOSPHORYLASE IN HEPATOCYTES
GLUCOSE HAS TO BE PHOSPHORYLATED TO ACTIVATE GLYCOGEN-SYNTHASE, BUT NOT TO INACTIVATE GLYCOGEN-PHOSPHORYLASE IN HEPATOCYTES
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DOI：
10.1016/0014-5793(92)80381-p
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发表时间：
1992-01-20
期刊：
影响因子：
3.5
通讯作者：
GUINOVART, JJ
中科院分区：
文献类型：
--
作者：
CARABAZA, A;CIUDAD, CJ;GUINOVART, JJ
2-脱氧葡萄糖和5-硫代葡萄糖与葡萄糖一样，引起大鼠肝细胞糖原磷酸化酶失活和糖原合成酶激活。然而，6-脱氧葡萄糖和1，5-脱水葡萄糖醇不会增加糖原合成酶的激活状态而使磷酸化酶失活。在3-O-甲基葡萄糖作用下，这些酶的活性没有发生变化。这些结果证明，虽然葡萄糖是触发磷酸化酶失活的分子，但葡萄糖6-磷酸是葡萄糖合成酶激活的信号，并且控制糖原合成酶激活状态的代谢物在肝细胞中起作用。
2-Deoxyglucose and 5-thioglucose, in the same fashion as glucose, cause the inactivation of the rat hepatocyte glycogen phosphorylase and the activation of glycogen synthase. However, 6-deoxyglucose and 1,5-anhydroglucitol inactivate phosphorylase without increasing the activation state of glycogen synthase. With 3-O-methylglucose no changes in the activity of these enzymes occurred. These results prove that while glucose is the molecule that triggers the inactivation of phosphorylase, glucose 6-phosphate is the signal for glucose synthase activation and that a metabolite control of the activation state of glycogen synthase is operative in hepatocytes.