An estimate for character sums

An estimate for character sums
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DOI:
10.1090/s0894-0347-1989-0965007-8
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发表时间:
1989-05
影响因子:
3.9
通讯作者:
N. M. Katz
N. M. Katz
中科院分区:
数学1区
文献类型:
--
作者:
N. M. Katz

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事实证明,考虑以下更一般的情况是有限的领域,n〜1是一个整数,b是f(i,e。 f的扩展,存在k-Algebras b®fk:。= k x k x···· b的detf(t x i b)在b的常规表示中本身具有n个独特的特征值(就上述同构而言,b®f k:。:: = k x k x ... x k,x k,x k,x k,仅当x®1:。:: =(xi' ,x n)具有所有不同组件x j•或均等的x是规则的,并且仅当b等于x生成的f-subalgebra f [x]。元素x是常规的,并且仅当f(x)= E时才是常规的。
It turns out to be easier to consider the following more general situation. F is a finite field, n ~ 1 is an integer, and B is a finite etale F -algebra of dimension n over F (i,e., over a finite extension K of F, there exists an isomorphism of K-algebras B ®F K:.::= K x K x··· x K). We assume given an element x in B that is regular in the sense that its characteristic polynomial detF(T x I B) in the regular representation of B on itself has n distinct eigenvalues. (In terms of the above isomorphism B ® F K :.::= K x K x ... x K, x is regular if and only if x ® 1 :.::= (XI' , •.• x n ) with all distinct components x j • Or equivalently, x is regular if and only if B is equal to the F-subalgebra F[x] generated by x. In the special case when B is a field F , the element x is regular if and only if F(x) = E.)