Distances on rhombus tilings

Distances on rhombus tilings
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菱形平铺上的距离

DOI:
10.1016/j.tcs.2011.04.015
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发表时间:
2009
期刊:
Theor. Comput. Sci.
影响因子:
--
通讯作者:
É. Rémila
É. Rémila
中科院分区:
--
文献类型:
--
作者:
O. Bodini;Thomas Fernique;M. Rao;É. Rémila

文献摘要

被引文献

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已知欧氏平面的单连通域的菱形镶嵌形成翻转连通空间(翻转是菱形镶嵌上的基本运算,其将由三个菱形组成的六边形旋转180 °)。出于对准晶生长模型的研究,我们在这里有兴趣更好地了解“紧”菱形平铺空间是如何翻转连接的。我们引入了一个下界(汉明距离)的最小数量的翻转连接两个平铺(翻转距离),我们调查它是否是尖锐的。答案取决于镶嵌中不同边缘方向的数量n:对于n=3(二聚体镶嵌)或n=4(八边形镶嵌)为正,但对于n=5(十边形镶嵌)或更大的n值可能为负。对于n=3和n=4的情况提供了标准证明,而n=5情况的复杂性导致了计算机辅助证明(其主要结果可以很容易地手动检查)。
The rhombus tilings of a simply connected domain of the Euclidean plane are known to form a flip-connected space (a flip is the elementary operation on rhombus tilings which rotates 180∘a hexagon made of three rhombi). Motivated by the study of a quasicrystal growth model, we are here interested in better understanding how “tight” rhombus tiling spaces are flip-connected. We introduce a lower bound (Hamming-distance) on the minimal number of flips to link two tilings (flip-distance), and we investigate whether it is sharp. The answer depends on the number n of different edge directions in the tiling: positive for n=3 (dimer tilings) or n=4 (octagonal tilings), but possibly negative for n=5 (decagonal tilings) or greater values of n. A standard proof is provided for the n=3 and n=4 cases, while the complexity of the n=5 case led to a computer-assisted proof (whose main result can however be easily checked manually).