Maps on simple algebras preserving zero products. II. Lie algebras of linear type.
Maps on simple algebras preserving zero products. II. Lie algebras of linear type.
复制标题
DOI:
10.2140/pjm.1981.92.469
复制
发表时间:
1981-02
影响因子:
0.6
通讯作者:
W. J. Wong
中科院分区:
文献类型:
--
作者:
W. J. Wong
Introduction* In [8] we began the study of the semilinear maps on an algebra over a field k which preserve zero products, a problem arising from recent investigations characterizing the linear transformations on the n x n matrix algebra Mn(k) over k which preserve various properties, particularly the work of Watkins on maps preserving commuting pairs of matrices [7]. If L is a Lie algebra, this means that we are concerned with the bijective semilinear maps f on L such that [f(x), f(y)] — 0 for all pairs of elements x, y of L such that [x, y] — 0. We say that / preserves zero Lie products. If L is finite-dimensional, these maps / form a group G(L) [8]. Clearly G(L) contains the group G± of all semilinear automorphisms and anti-automorphisms (semilinear maps which are automorphisms or anti-automorphisms of the multiplicative structure of L), the group of units G2 of the centroid of L (the algebra of linear transformations which commute with left multiplications in L), and the group Gs of all bijective transformations / of the form f(x) = x + g(x), where g is a linear map of L into its center Z(L). Let GQ(L) = GXG2GZ. In this paper we determine G(L), for a class of simple Lie algebras L, These are obtained by taking finite-dimensional simple associative algebras A over a field k and forming the Lie algebra L — [A, A]l[A, A] Π Z(A), where [A, A] is the subspace spanned by all the commutators [x, y] = xy — yx, and Z(A) is the center of A. If A is noncommutative, then L is a simple Lie algebra, except when A has characteristic 2 and is 4-dimensional over Z{A) [1, p. 17]. Except for cases of "small length/' we show that G(L) = G0(L) for such a Lie algebra L. In fact, we can deal with a wider class of