Kelvin transform for Grushin operators and critical semilinear equations

Kelvin transform for Grushin operators and critical semilinear equations
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DOI:
10.1215/s0012-7094-05-13115-5
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发表时间:
2006-01
影响因子:
2.5
通讯作者:
R. Monti;Daniele Morbidelli
R. Monti;Daniele Morbidelli
中科院分区:
数学1区
文献类型:
--
作者:
R. Monti;Daniele Morbidelli

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我们研究 R = R × R 中关键方程 xu+ (α + 1)2|x|2α yu = −u(Q+2)/(Q−2) 的正整数解 u = u(x, y), (1) 其中 (x, y) ∈ Rm×Rk ,α > 0,且 Q = m+ k(α+1)。在本文的第一部分中,利用方程相对于合适的共形反演的不变性,我们证明了解的“球对称”结果。在第二部分中,我们展示如何使用双曲对称论证来减少问题的维度。给定 (1) 的任何正解 u,在对变量 y 进行适当的缩放和平移之后,函数 v(x) = u(x, 0) 满足方程 divx(p∇xv) − qv = −pv(Q+2)/(Q−2), |x| < 1, (2) 具有混合边界条件。这里,p和q是适当的径向函数。在最后一部分中,我们证明如果m = k = 1,则(2)的解是唯一的,并且当m ≥ 3且k = 1时,问题(2)在x径向函数类中具有唯一解。
We study positive entire solutions u = u(x, y) of the critical equation xu+ (α + 1)2|x|2α yu = −u(Q+2)/(Q−2) in R = R × R, (1) where (x, y) ∈ Rm×Rk , α > 0, and Q = m+ k(α+1). In the first part of the article, exploiting the invariance of the equation with respect to a suitable conformal inversion, we prove a “spherical symmetry” result for solutions. In the second part, we show how to reduce the dimension of the problem using a hyperbolic symmetry argument. Given any positive solution u of (1), after a suitable scaling and a translation in the variable y, the function v(x) = u(x, 0) satisfies the equation divx(p∇xv) − qv = −pv(Q+2)/(Q−2), |x| < 1, (2) with a mixed boundary condition. Here, p and q are appropriate radial functions. In the last part, we prove that if m = k = 1, the solution of (2) is unique and that for m ≥ 3 and k = 1, problem (2) has a unique solution in the class of x-radial functions.