On the number of spanning trees of some irregular line graphs

On the number of spanning trees of some irregular line graphs
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关于一些不规则线图的生成树数

DOI:
10.1016/j.jcta.2013.06.005
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发表时间:
2013-09
期刊:
Journal of Combinatorial Theory - Series A
影响因子:
--
通讯作者:
Weigen Yan
Weigen Yan
中科院分区:
其他
文献类型:
--
作者:
Weigen Yan

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设G是一个n点m边的图,Δ和δ是G的最大度和最小度,G‘是在G的每个顶点v上附加Δ−d G(V)支边得到的图.众所周知,如果G是正则的(即Δ=δ,G=G’),则记为L(G)的线图有2 m−n+1Δm−n−1 t(G)生成树,其中t(G)是G的生成树数.本文证明了如果G是不规则的(即,G=G‘).Δ≠δ),则t(L(G‘))=2m−n+1Δm+S−n−1 t(G),其中S是G’中的一次顶点数。
Let G be a graph with n vertices and m edges and Δ and δ the maximum degree and minimum degree of G. Suppose G′ is the graph obtained from G by attaching Δ− d G (v) pendent edges to each vertex v of G. It is well known that if G is regular (ie, Δ= δ, G= G′), then the line graph of G, denoted by L (G), has 2 m− n+ 1 Δ m− n− 1 t (G) spanning trees, where t (G) is the number of spanning trees of G. In this paper, we prove that if G is irregular (ie, Δ≠ δ), then t (L (G′))= 2 m− n+ 1 Δ m+ s− n− 1 t (G), where s is the number of vertices of degree one in G′.
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