Precise Measurement of Retinal Vascular Bed Area and Density on Ultra-wide Fluorescein Angiography in Normal Subjects
Precise Measurement of Retinal Vascular Bed Area and Density on Ultra-wide Fluorescein Angiography in Normal Subjects
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DOI：
10.1016/j.ajo.2018.01.036
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发表时间：
2018-04-01
影响因子：
4.2
通讯作者：
Sadda, Srinivas R.
中科院分区：
文献类型：
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作者：
Fan, Wenying;Uji, Akihito;Sadda, Srinivas R.
目的：利用立体校正超宽场（UWF）荧光素血管造影（FA）表征和量化正常眼睛视网膜血管床总面积（RVBA）和血管密度（VD）。设计：横断面研究。方法：使用Optos 200Tx （Optos plc, Dunfermline, uk）对31名无眼部疾病的正常受试者59只眼睛进行FA检查。中央和外围引导的FA图像被蒙太奇和立体投影。早期FA用于提取视网膜血管作为二元掩膜。两个独立的，蒙面阅读中心认证的评分者在中间相位框架上描绘了视网膜总面积（TRA）的外围边缘。RVBA和TRA使用制造商提供的软件以mm(2)为单位自动计算。VD由RVBA除以TRA计算。结果：整个视网膜的平均RVBA为42.3 +/- 14.8 mm(2)，男女受试者之间无差异（P =.439），左右眼之间无差异（P =.407）。整个视网膜的平均VD为4.3% +/- 1.4%，无性别差异（P = 0.629）或侧边差异（P = 0.426）。年龄与RVBA、VD均呈负相关(RVBA: R = -0.6， P
PURPOSE: To characterize and quantify the total retinal vascular bed area (RVBA) and vascular density (VD) in normal eyes using stereographically corrected ultra-wide field (UWF) fluorescein angiography (FA).DESIGN: Cross-sectional study.METHODS: Fifty-nine eyes of 31 normal subjects with no evidence of ocular disease underwent FA using the Optos 200Tx (Optos plc, Dunfermline, United Kingdom). Central and peripheral-steered FA images were montaged and stereographically projected. The early-phase FA was used to extract the retinal vasculature as a binary mask. Two independent, masked reading center-certified graders delineated the peripheral edge of the total retinal area (TRA) on a middle-phase frame. The RVBA and TRA were computed automatically in mm(2) using software provided by the manufacturer. The VD was calculated by dividing RVBA by TRA.RESULTS: The mean RVBA was 42.3 +/- 14.8 mm(2) for the entire retina, with no difference between male and female subjects (P =.439) or between right and left eyes (P =.407). The mean VD was 4.3% +/- 1.4% for the entire retina, with no difference based on sex (P =.629) or laterality (P =.426). A negative correlation was observed between age and both RVBA and VD (RVBA: R = -0.6, P