A Generalization of a result of Sinnott

A Generalization of a result of Sinnott
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辛诺特结果的推广

DOI:
10.2140/pjm.1997.181.225
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发表时间:
1997
影响因子:
0.6
通讯作者:
H. Kisilevsky
H. Kisilevsky
中科院分区:
数学4区
文献类型:
--
作者:
H. Kisilevsky

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证据。An+1是有限Gn+1-模,使得An+1=B∪C,其中B是An+1中不被Gn+1的任何非平凡元素固定的元素的集合,C=An+1\B。由于Gn+1是循环群,因此C的每个元素都被Gn+1中p阶子群固定,因此C⊆An=An。相反的包含是清楚的,所以C=An。算起来,|An+1|=|B|+|An|。由于B是轨道的并,每个轨道包含p个元素,因此它遵循|An+1|≡|An|(Modp)。
Proof. An+1 is a finite Gn+1-module so that An+1 = B ∪ C where B is the set of those elements in An+1 not fixed by any non-trivial element of Gn+1, and C = An+1 \ B. Since Gn+1 is a cyclic group it follows that every element of C is fixed by the the subgroup of order p in Gn+1, and so C ⊆ An = An. The opposite inclusion is clear so C = An. Counting we have, |An+1| = |B|+ |An|. Since B is a union of orbits each of which contains p elements it follows that |An+1| ≡ |An| (mod p).