Hamiltonicity thresholds in Achlioptas processes

Hamiltonicity thresholds in Achlioptas processes
复制标题

Achlioptas 过程中的哈密顿度阈值

DOI:
10.1002/rsa.20302
复制
发表时间:
2008
影响因子:
1
通讯作者:
B. Sudakov
B. Sudakov
中科院分区:
数学3区
文献类型:
--
作者:
Michael Krivelevich;E. Lubetzky;B. Sudakov

文献摘要

被引文献

相似文献

在这篇文章中,我们分析了一个汉密尔顿循环的出现在以下随机过程。该过程从nlabeled顶点上的空图开始。在每一轮中,我们都会看到K = K(n)条边,这些边是从缺失的边中随机均匀选择的,并要求我们将其中一条边添加到当前图中。我们的目标是尽快创造一个汉密尔顿周期。我们表明,这个问题有三个政权,取决于K的值。对于K = o(log n),哈密尔顿性的阈值是${1 + o(1)\over 2K}$n log n,即,典型地,我们可以构造比通常的随机图过程快K倍的汉密尔顿循环。当K = ω(log n)时,我们基本上可以几乎不浪费边,并且以高概率在n + o(n)轮中创建汉密尔顿循环。最后,在K = Θ(log n)的中间状态中,阈值具有阶数,我们获得相差3倍的上界和下界。© 2010 Wiley Periodicals,Inc.随机结构算法,2010
In this article, we analyze the appearance of a Hamilton cycle in the following random process. The process starts with an empty graph on nlabeled vertices. At each round we are presented with K = K(n) edges, chosen uniformly at random from the missing ones, and are asked to add one of them to the current graph. The goal is to create a Hamilton cycle as soon as possible. We show that this problem has three regimes, depending on the value of K. For K = o(log n), the threshold for Hamiltonicity is ${1 + o(1) \over 2K}$n log n, i.e., typically we can construct a Hamilton cycle K times faster that in the usual random graph process. When K = ω(log n) we can essentially waste almost no edges, and create a Hamilton cycle in n + o(n) rounds with high probability. Finally, in the intermediate regime where K = Θ(log n), the threshold has order nand we obtain upper and lower bounds that differ by a multiplicative factor of 3. © 2010 Wiley Periodicals, Inc. Random Struct. Alg., 2010