Free‐radical homopolymerization and copolymerization of vinylferrocene
Free‐radical homopolymerization and copolymerization of vinylferrocene
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乙烯基二茂铁的自由基均聚和共聚
DOI：
10.1002/pol.1971.150090307
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发表时间：
1971
期刊：
影响因子：
--
通讯作者：
C. Pittman
中科院分区：
文献类型：
--
作者：
John C. Lai;Thane Rounsfell;C. Pittman
以偶氮二异丁腈为引发剂，在苯溶液中聚合乙烯基二茂铁，得到了一系列苯溶性均聚物。因此，自由基共聚研究与苯乙烯、丙烯酸甲酯、甲基丙烯酸甲酯、丙烯腈、醋酸乙烯和异戊二烯在苯中进行。在这些条件下，除了醋酸乙烯和异戊二烯不能与乙烯基二茂铁形成共聚物外，共聚物的生产都很顺利。采用曲线拟合法对共聚物方程的微分形式进行拟合，采用Fineman-Ross技术对共聚物方程的积分形式进行计算机拟合，得到了乙烯基二铁-苯乙烯共聚反应的相对反应性比r1和r2。在苯乙烯（M2）共聚反应中，曲线拟合法和Fineman-Ross法得到的r1 = 0.08, r2 = 2.50，积分法得到的r1 = 0.097, r2 = 2.91。将积分法应用于丙烯酸甲酯和甲基丙烯酸甲酯（M2），得到r1 = 0.82, r2 = 0.63；R1 = 0.52, r2 = 1.22。曲线拟合法得到丙烯腈（M2）共聚反应的r1 = 0.15, r2 = 0.16。在苯乙烯共聚反应中，乙烯基二茂铁的Q值为0.145，e值为0.47。
The benzene solution homopolymerization of vinylferrocene, initiated by azobisisobutyronitrile, gave a series of benzene-soluble homopolymers. Thus, free-radical copolymerization studies were performed with styrene, methyl acrylate, methyl methacrylate, acrylonitrile, vinyl acetate, and isoprene in benzene. With the exception of vinyl acetate and isoprene, which did not give copolymers with vinylferrocene under these conditions, smooth production of copolymers occurred. The relative reactivity ratios, r1 and r2, were obtained for vinylferrocene–styrene copolymerizations by using the curve-fitting method for the differential form of the copolymer equation, by the Fineman-Ross technique, and by computer fitting of the integrated form of the copolymer equations applied to higher conversion copolymerizations. In styrene (M2) copolymerizations, the curve-fitting and Fineman-Ross methods both gave r1 = 0.08, r2 = 2.50, while the integration method gave r1 = 0.097, r2 = 2.91. Application of the integration method to methyl acrylate and methyl methacrylate (M2) gave values of r1 = 0.82, r2 = 0.63; r1 = 0.52, r2 = 1.22, respectively. The curve-fitting method gave r1 = 0.15, r2 = 0.16 for acrylonitrile (M2) copolymerizations. From styrene copolymerizations, vinylferrocene exhibited values of Q = 0.145 and e = 0.47.