Tangle Equations II
Tangle Equations II
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缠结方程 II
DOI：
10.1142/s0218216597000029
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发表时间：
1997
影响因子：
0.5
通讯作者：
C. Ernst
中科院分区：
文献类型：
--
作者：
C. Ernst
给定两个4平面K1和K2。设O是有理缠结之和，使得N（O+P）=K1，N（O+R）=K2，其中P和R是有理缠结，N分别是缠结O+P和O+R上的分子结构.在O为非有理数的情况下，本文给出了求解O，P和R的方程组的一个算法。如果给出两个形式为N（O+R+R）=K3和N（O+R+R+R+）=K4的附加方程，并且其中一个Ki是手性的，则O和R至多有一个解。如果所有Ki都是非手性的，那么最多有一个解决方案及其镜像。
Given two 4-plats K1 and K2. Let O be a sum of rational tangles such that N(O+P)=K1 and N(O+R)=K2, where P and R are rational tangles and N is the numerator construction on the tangles O+P and O+R, respectively. An algorithm is presented here to solve such a system of equations for O, P and R in the case where O is non rational. If two additional equations of the form N(O+R+R)=K3 and N(O+R+R+R+) =K4 are given and one of the Ki is chiral, then there is at most one solution for O and R. If all Ki are achiral then there is at most one solution together with its mirror image.