Disproportionation of Sn(II){CH(SiMe 3 ) 2 } 2 to ·Sn(III){CH(SiMe 3 ) 2 } 3 and ·Sn(I){CH(SiMe 3 ) 2 }: Characterization of the Sn(I) Product
Disproportionation of Sn(II){CH(SiMe 3 ) 2 } 2 to ·Sn(III){CH(SiMe 3 ) 2 } 3 and ·Sn(I){CH(SiMe 3 ) 2 }: Characterization of the Sn(I) Product
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Sn(II){CH(SiMe 3 ) 2 } 2 歧化为·Sn(III){CH(SiMe 3 ) 2 } 3 和·Sn(I){CH(SiMe 3 ) 2 }：表征
DOI：
10.1039/d3cc01542d
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发表时间：
2023
影响因子：
4.9
通讯作者：
Power, Philip P
中科院分区：
文献类型：
--
作者：
Mears, Kristian;Nguyen, Gia-Ann;Ruiz, Bronson;Zou, Wenxing;Fettinger, James C;Power, Philip P
半个世纪后，Lappert 的二烷基亚锡 SnR2，R = CH(SiMe3)2 (1) 发生光解歧化，得到持久性三价自由基 [˙SnR3]，现在描述了相应 Sn(I) 产物 ˙SnR 的表征。通过 Mg(I) 试剂 Mg(BDIDip)2（BDI = (DipNCMe)2CH，Dip = 2,6-二异丙基苯基）还原 1，将其分离为六锡棱柱烷 Sn6R6 (2)。
Half a century after the photolytic disproportionation of Lappert's dialkyl stannylene SnR2, R = CH(SiMe3)2 (1) gave the persistent trivalent radical [˙SnR3], the characterization of the corresponding Sn(I) product, ˙SnR is now described. It was isolated as the hexastannaprismane Sn6R6 (2), from the reduction of 1 by the Mg(I)-reagent, Mg(BDIDip)2 (BDI = (DipNCMe)2CH, Dip = 2,6-diisopropylphenyl).