MOD-score analysis with simple pedigrees: An overview of likelihood-based linkage methods
MOD-score analysis with simple pedigrees: An overview of likelihood-based linkage methods
复制标题
DOI：
10.1159/000102992
复制
发表时间：
2007-01-01
期刊：
影响因子：
1.8
通讯作者：
Strauch, Konstantin
中科院分区：
文献类型：
--
作者：
Strauch, Konstantin
一个MOD得分分析，其中参数LOD得分最大化的性状模型参数，可以是一个强大的方法复杂的性状的映射。对于受影响的同胞对，在无连锁的零假设下，MOD评分渐进地遵循自由度为2、1和0的卡方（2）分布的混合。在这种情况下，MOD分数分析产生了一些（尽管有限）关于特质模型参数的信息，并且与简单的LOD分数分析相比，有可能增加功效。这里，它表明，与单线性影响的相对对，MOD分数渐近遵循卡方（2）分布的混合与1和0自由度的零假设下，即，相同的分布，其次是简单的LOD分数。在此设置中无法获得关于特质模型的信息，并且与LOD分数分析相比，没有获得功效。展望更大的谱系。MOD评分零分布背后的自由度数量取决于所研究的谱系类型，对应于与功效相关的探索维度数量以及可以联合估计的参数数量。版权所有（c）2007 S. Karger AG，巴塞尔。
A MOD-score analysis, in which the parametric LOD score is maximized with respect to the trait-model parameters, can be a powerful method for the mapping of complex traits. With affected sib pairs, it has been shown before that MOD scores asymptotically follow a mixture of chi(2) distributions with 2, 1 and 0 degrees of freedom under the null hypothesis of no linkage. In that context, a MOD-score analysis yields some ( albeit limited) information regarding the trait-model parameters, and there is a chance for an increased power compared to a simple LOD-score analysis. Here, it is shown that with unilineal affected relative pairs, MOD scores asymptotically follow a mixture of chi(2) distributions with 1 and 0 degrees of freedom under the null hypothesis, that is, the same distribution as followed by simple LOD scores. No information regarding the trait model can be obtained in this setting, and no power is gained when compared to a LOD-score analysis. An outlook to larger pedigrees is given. The number of degrees of freedom underlying the null distribution of MOD scores, that depends on the type of pedigrees studied, corresponds to the number of explored dimensions related to power and to the number of parameters that can jointly be estimated. Copyright (c) 2007 S. Karger AG, Basel.