Corrigendum to “Optimal decay rates for a chemotaxis model with logistic growth, logarithmic sensitivity and density-dependent production/consumption rate” [J. Differential Equations (2020) 1379–1411]

Corrigendum to “Optimal decay rates for a chemotaxis model with logistic growth, logarithmic sensitivity and density-dependent production/consumption rate” [J. Differential Equations (2020) 1379–1411]
复制标题

对“具有逻辑增长、对数敏感性和密度依赖的生产/消耗率的趋化模型的最佳衰减率”的勘误[J.

DOI:
10.1016/j.jde.2020.04.027
复制
发表时间:
2020
影响因子:
2.4
通讯作者:
Zhao, Kun
Zhao, Kun
中科院分区:
数学2区
文献类型:
--
作者:
Zeng, Yanni;Zhao, Kun

文献摘要

参考文献

相似文献

在文[1]的第5节(定理2.2的证明)中,假定(5.14)中ε> 0。虽然它适用于ε> 0,但该方法需要针对ε= 0的情况进行修改。本勘误表的目的是提供一种替代方法,它取代引理5.2和引理5.3的证明,并且对ε= 0和ε> 0都有效。根据[1]的(5.11),(5.10),(5.4)和(1.13),<$(x,t)= s(x,t)− s= s [exp <$(D × <$(x μ K D x,x μ K D t))− 1]。根据平均值定理,(1)|n(x,t)|≤ C|(χ μ K D x,χ μ K D t)|expr(D| χ|其中,C= s D/| χ|是一个常数。我们的目标是证明(2)n = 1 ≤ C(t+ 1)− 1 4,t≥ 2,其中常数C> 0取决于系统参数和初始数据。一旦我们证明了(2),Sobolev不等式和关于v的估计,见[1]中的(4.11),(1.13),(2.3)和(2.4),意味着(3)<$L∞(t)≤ C <$1 2 <$v <$1 2≤ C(t+ 1)− 1 2,t≥ 2。将(2)和(3)代入(1)得到(4)当t≥ 2 D/(χ μ K)时,当t≤ 2D/(χ μ K)时,由于[1]中的引理5.1限制了λ λ(t)的界,所以t≤ 2D/(χ μ K)是平凡的.方程(4)是[1]中的(5.24),因此其中的引理5.3是合理的。根据(1)和(3),引理5.2也是合理的。[1]中的其余证明(在引理5.3之后)仍然有效。
In Section 5 of our previous paper [1](the proof of Theorem 2.2), it is presumed ε> 0 in (5.14) therein. While it works for ε> 0, the approach needs to be modified for the case ε= 0. The purpose of this corrigendum is to provide an alternative, which is to replace the proofs of Lemma 5.2 and Lemma 5.3, and is valid for both ε= 0 and ε> 0.From (5.11),(5.10),(5.4) and (1.13) of [1], ϕ (x, t)= s (x, t)− s= s [exp⁡(D χ ψ (χ μ K D x, χ μ K D t))− 1]. Thus by the mean value theorem,(1)| ϕ (x, t)|≤ C| ψ (χ μ K D x, χ μ K D t)| exp⁡(D| χ|‖ ψ‖ L∞(χ μ K D t)), where C= s D/| χ| is a constant. Our goal here is to prove (2)‖ ψ‖(t)≤ C (t+ 1)− 1 4, t≥ 2, with a constant C> 0 depending on the system parameters and initial data. Once we have proved (2), the Sobolev inequality and the estimates on v, see (4.11),(1.13),(2.3) and (2.4) in [1], imply (3)‖ ψ‖ L∞(t)≤ C‖ ψ‖ 1 2‖ v‖ 1 2≤ C (t+ 1)− 1 2, t≥ 2. Substituting (2) and (3) into (1) gives us (4)‖ ϕ‖(t)≤ C‖ ψ‖(χ μ K D t)≤ C (t+ 1)− 1 4 for t≥ 2 D/(χ μ K). The case t≤ 2 D/(χ μ K) is trivial since‖ ϕ‖(t) is bounded by Lemma 5.1 in [1]. Equation (4) is (5.24) in [1] hence Lemma 5.3 therein is justified. Lemma 5.2 is also justified in view of (1) and (3). The rest of the proof (after Lemma 5.3) in [1] stays valid.
DOI: 10.1016/j.jde.2019.08.050
发表时间: 2020-02
影响因子: 2.4
作者:
Yanni Zeng;Kun Zhao
通讯作者: Yanni Zeng;Kun Zhao