Relation between the skew-rank of an oriented graph and the rank of its underlying graph

Relation between the skew-rank of an oriented graph and the rank of its underlying graph
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DOI:
10.1016/j.ejc.2015.12.005
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发表时间:
2016-05
期刊:
Eur. J. Comb.
影响因子:
--
通讯作者:
Dein Wong;Xiaobin Ma;Fenglei Tian
Dein Wong;Xiaobin Ma;Fenglei Tian
中科院分区:
其他
文献类型:
--
作者:
Dein Wong;Xiaobin Ma;Fenglei Tian

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定向图G σ是一个不含圈和重弧的有向图,这里G称为G σ的底层图.设S(G σ)表示G σ的斜邻接矩阵,A(G)表示G的邻接矩阵. G σ的斜秩记为sr(G σ),指的是S(G σ)的秩,由于S(G σ)是斜对称的,所以S(G σ)的秩总是偶数。一个很自然的问题是:有向图G σ的斜秩与其基础图的秩之间的关系如何?在本文中,我们集中注意力在这个问题上。用d(G)表示G的循环空间的维数,即d(G)=| E(G)|−| V(G)|+ θ(G),其中θ(G)表示G的连通分支数.证明了对定向图G σ,sr(G σ)≤ r(G)+2d(G),刻画了斜秩达到上界的定向图G σ.
An oriented graph G σ is a digraph without loops and multiple arcs, where G is called the underlying graph of G σ. Let S (G σ) denote the skew-adjacency matrix of G σ, and A (G) be the adjacency matrix of G. The skew-rank of G σ, written as s r (G σ), refers to the rank of S (G σ), which is always even since S (G σ) is skew symmetric. A natural problem is: How about the relation between the skew-rank of an oriented graph G σ and the rank of its underlying graph? In this paper, we focus our attention on this problem. Denote by d (G) the dimension of cycle spaces of G, that is d (G)=| E (G)|−| V (G)|+ θ (G), where θ (G) denotes the number of connected components of G. It is proved that s r (G σ)≤ r (G)+ 2 d (G) for an oriented graph G σ, the oriented graphs G σ whose skew-rank attains the upper bound are characterized.