On mullineux' conjecture in the representation theory of symmetric groups
On mullineux' conjecture in the representation theory of symmetric groups
复制标题
论对称群表示论中的穆利纽猜想
DOI:
10.1080/00927879708825953
复制
发表时间:
1997
影响因子:
0.7
通讯作者:
Maozhi Xu
中科院分区:
文献类型:
--
作者:
Maozhi Xu
A well-known fact in the representation theory of symmetric groups is that we can index ordinary irreducibles and p-modular irreducibles by Young diagrams and p-row regular Young diagrams respectively [J2][J3, § 11]. Let X, be partitions of n as usual. We use SX, SJ'to denote Specht modules and if p is p-row regular, we use DJ'to denote the quotient of SJ'by its unique maximal submodule SJ'n SwL. When we tensor DJ'with the alternating representation, we obtain another irreducible. How do their indices relate to each other? Mullineux conjectured a solution to this problem [Mull. James suggested some years later that this problem should be solved [J3]. To make things easier we call the problem James' problem and the conjecture Mullineux'conjecture. The correctness of it for several special cases can be found in the literature, for example [Mu21 for the p-core cases,[XI for the cases related to hooks. However it is only recently that Mullineux'conjecture has been reduced to a purely combinatorial statement by a series of papers of Kleshchev [Kl][K2][K3], and a very long and complicated proof of this combinatorial statement was given by Ford and Kleshchev [FK]. Then Bessenrodt and Olsson gave a shorter proof of this combinatorial statement by the invention of the residue symbol for p-row regular diagramslBO]. However a complete proof of Mullineux'conjecture is still too long.The main result of this paper is to give a new construction of Mullineux'correspondence among p-row regular Young diagrams [Mull. Our construction is more subtle and it can be easily used to obtain what we called p-evaluations of p-row regular diagrams. We shall use these result to propose another stronger conjecture. It is also cornbinatorial, but is different from Kleshchev's. Our combinatorial conjecture implies Mullineux'conjecture. If a short proof of it could be given, then a short proof of Mullineux'conjecture would follow.